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Matematika Peminatan

Matematika Peminatan

Assessment

Presentation

•

Mathematics

•

12th Grade

•

Easy

Created by

gading purnaman

Used 13+ times

FREE Resource

7 Slides • 10 Questions

1

Matematika Peminatan


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Multiple Choice

Nilai dari  lim⁡x→π12tan⁡ 2xtan⁡ 3x\lim_{x\rightarrow\frac{\pi}{12}}\frac{\tan\ 2x}{\tan\ 3x}  adalah ...

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3

2

 3\sqrt{3}  

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 133\frac{1}{3}\sqrt{3}  

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 123\frac{1}{2}\sqrt{3}  

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1

9

Multiple Choice

Nilai dari  lim⁡x→1(tan⁡(x−1)x3−1)\lim_{x\rightarrow1}\left(\frac{\tan\left(x-1\right)}{x^3-1}\right)  adalah ....

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 13\frac{1}{3}  

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 −13-\frac{1}{3}  

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1

4

-1

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 12\frac{1}{2}  

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Multiple Choice

 lim⁡x→ π4 cos⁡ 2xcos⁡ x −sin⁡ x=...\lim_{x\rightarrow\ \frac{\pi}{4}}\ \frac{\cos\ 2x}{\cos\ x\ -\sin\ x}=...  

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-1

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-2

3

 2\sqrt{2}  

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1

11

Multiple Choice

 lim⁡x→1 (x2−1).2( x−1)−2 sin⁡2 (x−1)=...\lim_{x\rightarrow1}\ \frac{\left(x^2-1\right).2\left(\ x-1\right)}{-2\ \sin^2\ \left(x-1\right)}=...  

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-1

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-2

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-1/2

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1

12

Multiple Choice

 lim⁡x→0 x tan⁡ 3xsin⁡2 6x=...\lim_{x\rightarrow0}\ \frac{x\ \tan\ 3x}{\sin^2\ 6x}=...  

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1/6

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1/3

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1/12

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3/9

13

Multiple Choice

 lim⁡x→0 2sin⁡ 2x3 tan⁡ 3x=...\lim_{x\rightarrow0}\ \frac{2\sin\ 2x}{3\ \tan\ 3x}=...  

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2/3

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1

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1/3

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4/9

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Multiple Choice

 lim⁡x→0 sin⁡ 3x−sin⁡ 2x4x=...\lim_{x\rightarrow0}\ \frac{\sin\ 3x-\sin\ 2x}{4x}=...  

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3/4

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1/2

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1/4

4

0

15

Multiple Choice

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6

2

3

3

2

4

1

5

0

16

Multiple Choice

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12

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4

3

3

4

1

5

0

17

Multiple Choice

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6

2

3

3

2

4

1

5

0

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Matematika Peminatan


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