Potenciación y Radicación de Fraccionarios

Una potencia consiste en multiplicar la base tantas veces como lo indique el exponente:

 $3^4=3\cdot3\cdot3\cdot3=3\times3\times3\times3=81$  

 $\left(\frac{39}{47}\right)^0=1\ \ \ \ \ \ \ \ \ \ \ \ \left(-\frac{11}{13}\right)^0=1\ \ \ \ \ \ \ \ \ \ \ \ \left(\frac{9}{7}\right)^0=1$    $\left(\frac{7}{9}\right)^5\cdot\left(\frac{7}{9}\right)^6=\left(\frac{7}{9}\right)^{5+6}=\left(\frac{7}{9}\right)^{11}$  $\left(\frac{12}{5}\right)^1=\frac{12}{5}\ \ \ \ \ \ \ \ \ \left(-\frac{15}{4}\right)^1=-\frac{15}{4}\ \ \ \ \ \ \ \ \ \ \left(\frac{3}{13}\right)^1=\frac{3}{13}$   $\left(\frac{8}{3}\right)^4\ \cdot\ \left(\frac{5}{4}\right)^4=\left(\frac{8}{3}\cdot\frac{5}{4}\right)^4=\left(\frac{40}{12}\right)^4=\left(\frac{10}{3}\right)^4$  

 $\left(\frac{13}{9}\right)^8\ \div\left(\frac{13}{9}\right)^6=\left(\frac{13}{9}\right)^{8-6}=\left(\frac{13}{9}\right)^2$  

 $\left\{\left(\frac{2}{5}\right)^3\right\}^4=\left(\frac{2}{5}\right)^{3\cdot4}=\left(\frac{2}{5}\right)^{12}$  

 $\left(\frac{1}{2}\right)^6\div\left(\frac{3}{5}\right)^6=\left(\frac{1\cdot5}{2\cdot3}\right)^6=\left(\frac{5}{6}\right)^6$