PROJECTILE MOTION

Given: Vx = 2.50m/s; h= 50.0 m; g= 9.8 m/s2

Find: Range and time

Formula: R = Vxt          ;          t = $\sqrt{\frac{2h}{g}}$  
A. Range (R) = 7.975 or 8 meters
B. time (t)= 3.19 seconds

Given: Vy = 15.0 m/s ; R = 60.0 m ; g= 9.8 m/s²

Find: height

Formula: h = gt²  / 2 ; Vy = gt or t = Vy / g

Answer : t = 1.53 seconds ; h = 11.47 meter

Given Vi=50.0 m/s     θ = 200

Unknown H =?

Formula: H = gt² / 2 ; V_y = V_i sinθ

h= (V_i sin ) (t) - (1/2) gt²

R = V_i2 sin2θ / g

Solution R = (50m/s)² sin2 (20) / 9.8 m/s²

Answer: R = 163.97 m or 164 m