Factoring and Solving Quadratics

Presentation

•

Mathematics

•

9th Grade

•

Medium

•

CCSS

HSA-REI.B.4B

Standards-aligned

Susan Chandler

Used 52+ times

FREE Resource

6 Slides • 10 Questions

Solving Review

Factoring and Solving Quadratics

We are going to continue reviewing factoring and extend that idea into SOLVING! :)

Multiple Choice

In order to factor the trinomial:

y=x^2+bx+c

we need to find to integers that....?

multiply to b

multiply to c

divide by b

divide by c

Multiple Choice

In order to factor the trinomial:

y=x^2+bx+c

we need to find to integers that....?

add to b

add to c

subtract to b

subtract to c

As an example, if we have x²+ 7x + 12

Factors of 12 are: 1 and 12, 2 and 6, 3 and 4, as well as their negatives

The only pair that adds up to 7 is 3 and 4.

This means we can factor it to: (x+3)(x+4)

Multiple Choice

Factor:

x^2+9x\ -36

(x + 12)(x - 3)

(x + 4)(x + 9)

(x - 12)(x - 3)

(x - 12)(x + 3)

Multiple Choice

Factor:

x^2+5x\ -6

(x + 5)(x - 6)

(x + 2)(x + 3)

(x - 6)(x - 1)

(x + 6)(x - 1)

Multiple Choice

Factor:

x^2+7x\ -30

(x + 5)(x - 6)

(x + 10)(x + 3)

(x - 3)(x + 10)

(x - 10)(x - 3)

To solve:

Once you have factored the equation -

Create an equation with each factor

Solve that equation.

(x-4) =0 and (x+5)=0

What would the answers be? Solve for each x

Multiple Choice

Solve for the values of x:

(x - 5)(x - 1) = 0

x = 5, 1

x = 5, -1

x = -5, 1

x = -5, -1

Multiple Choice

Solve for the values of x:

(x + 2)(x - 3) = 0

x = 2, 3

x = -2, -3

x = 2, 3

x = -2, 3

Now put it all together

Factor the trinomial
Solve each piece for x

Multiple Choice

Solve the equation by factoring:

x²- 6x = -8

x=2 and x=4

x= -2 and x= -4

x= -2 and x=4

x=2 and x= -4

Multiple Choice

Solve by factoring: x² - 9x + 20 = 0

x = -4 and x = -5

x = 20 and x = -9

x = 4 and x = 5

x = -4 and x = 5

Multiple Choice

Solve by factoring: x² + 3x - 18 = 0

x = -3 and x = 6

x = 3 and x = -6

x = -9 and x = 2

x = 9 and x = -2

Solving Review

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