x(3x² + 9x - 15)

3x(x² + 3x - 5)

3x(x² - 9x + 15)

x(3x² -9x + 15)

(x + 10)(x - 7)

(x - 10)(x + 3)

(x + 10)(x + 3)

(x + 10)(x - 3)

(2y + 3)(2y – 3)

(4y+1)(4y-9)

(2y + 3)(2y + 3)

(2y – 3)(2y – 3)

y = -2

x = 3

x = -3

y = 2

(3, -5)

(5, 7)

(7, -5)

(-5, 7)

x = -12, -1

x = 12, 1

x = 13, 1

x = -13, -1

x = -4 and x = -5

x = 20 and x = -9

x = 4 and x = 5

x = -4 and x = 5

All real numbers.

All real numbers greater than or equal to 0.

All real numbers greater than or equal to -2.

All real numbers greater than or equal to 2.

The ball was kicked from 500 centimeters from the ground and it traveled for 4 seconds.

The ball was kicked from the ground and it was in the air for 4 seconds.

The ball had a maximum height of 2000 centimeters and it was in the air for a total of 2 seconds.

The ball had a maximum height of 1000 centimeters and it was in the air for 4 seconds.

$$y=\left(x+4\right)\left(x+6\right)\$$

$$y=\left(x+5\right)^2-1$$

$$y=x^2+10x+24$$

$$y=\left(x+4\right)\left(x+6\right)\$$

$$y=\left(x+5\right)^2-1$$

$$y=x^2+10x+24$$

$$y=\left(x+4\right)\left(x+6\right)\$$

$$y=\left(x+5\right)^2-1$$

$$y=x^2+10x+24$$

Yes, she factored correctly and then used the zero product property

Yes, she factored correctly and then square rooted.

No, she did factor correctly, but she can't use the zero product property as shown.

No, she didn't factor correctly so the rest of her work is wrong.

x = {0 and 4}

x = {-4 and 0}

x = 0

x = -4

1 second

5 seconds

7 seconds

11 seconds

(x+7) (x-9)

(x-7) (x+9)

(x+7)(x+9)

(x-7)(x-9)

2 ft

80 ft

144 ft

64 ft

8 seconds

1 second

1.5 seconds

1/4 second

.25 ft

24 ft

25 ft

8 ft

(x - 8)(x + 3)

(x + 8)(x - 3)

(x + 6)(x - 4)

(x + 12)(x - 2)

( 3x + 5 ) (3x - 5 )

( 3x - 5 ) (3x - 5 )

( 3x + 5 ) (3x + 5 )

Unfactorable

$$\left(5p^2-1\right)\left(4p-5\right)$$  

$$\left(5p^2+1\right)\left(4p+5\right)$$  

$$\left(5p^2+1\right)\left(4p-5\right)$$  

$$\left(5p^2-1\right)\left(4p+5\right)$$  

$$\left(2p^2+3\right)\left(p+2\right)$$  

$$\left(2p^2+6\right)\left(p+4\right)$$  

$$\left(4p^2+3\right)\left(p+2\right)$$  

$$\left(4p^2+8p\right)\left(3p+6\right)$$  

$$y=ax^2+bx+c$$  

$$x=\frac{-b}{2a}$$  

$$y=mx+b$$  

$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$