Quadratics & Exponential

(2.4, 0)

(0, -1)

(-0.4, 0)

(1, -2)

I and II only

I and III only

II and III only

I, II, and III

I and II only

I and III only

II and III only

I, II, and III

$h\left(t\right)=-16t^2-64t$

$h\left(t\right)=-16t^2+128t-256$

$h\left(t\right)=-16t^2+64t$

$h\left(t\right)=-16t^2-128t-256$

$y=\frac{3}{4}\left(x+3\right)^2+7$

$y=-\frac{3}{4}\left(x+3\right)^2-7$

$y=\frac{3}{4}\left(x-3\right)^2+7$

$y=-\frac{3}{4}\left(x-3\right)^2-7$

-74 and 88

-2 and 16

-88  and 74

-16 and 2

The zeros are  $-\frac{5}{2}and\ -1,\ because\ f\left(x\right)=\left(x+1\right)\left(2x+5\right).$  

The zeros are  $-\frac{5}{2}and\ 1,\ because\ f\left(x\right)=\left(x-1\right)\left(2x+5\right).$  

The zeros are  $-1\ and\ \frac{5}{2},\ because\ f\left(x\right)=\left(x+1\right)\left(2x-5\right).$  

The zeros are  $1\ and\ \frac{5}{2},\ because\ f\left(x\right)=\left(x-1\right)\left(2x-5\right).$  

The graph of g is narrower than the graph of f

The graph of g is wider than the graph of f

the graph g is 7 units below the graph of f

The graph of g is 7 units above the graph of f

3x - 2

9x - 1

x - 2

2x - 1

x - 6

x - 2

x - 3

x - 1

$y\ge4.5$

$x\ge-2$

$y\ge-2$

$x\ge4.5$

$x\ge0$

$y\ge250,000$

$0\le x\le110$

$250,000\le y\le1,000,000$

The coordinates of the x-intercept are (0.13, 0).

The coordinates of the y-intercept are (0, 5).

The equation of the asymptote is x = 0.

The graph includes the point (2,1).

$f\left(x\right)=1,024\left(1.50\right)^x$

$f\left(x\right)=1,024\left(0.50\right)^x$

$f\left(x\right)=1,024\left(1.05\right)^x$

$f\left(x\right)=1,024\left(0.05\right)^x$

The initial balance of the account decreases at a rate of 97.3% each year.

The balance in the account increases at a rate of 2.7% each year.

The initial balance of the account was $1,027.

The balance in the account at the end of one year is $900.