

Viernes 23 abril
Presentation
•
Mathematics
•
University
•
Hard
Josué González
Used 1+ times
FREE Resource
5 Slides • 5 Questions
1
Otro Ejemplo
y′=xy+xcos2(xy)

2
Pasos generales
Reescribir para que diga M[x,y]dx + N[x,y]dy=0
¿Cuál es más simple?
Hacer el cambio de variable.
Simplificar
Integrar
Vamos por pasos:
3
Multiple Choice
Reescribir y′=xy+xcos2(xy)
(y+xcos2(xy))dx−xdy=0
xdx+(y+xcos2(xy))dy=0
(y+xcos2(xy))dx+xdy=0
4
Reescribir y′=xy+xcos2(xy)
dxdy=xy+xcos2(xy)
xdy=(y+xcos2(xy))dx
(y+xcos2(xy))dx−xdy=0
5
Multiple Choice
¿Cuál es el cambio de variable para
(y+xcos2(xy))dx−xdy=0
y=xu
x=yu
6
Multiple Choice
Aplicando y=xu a la ecuación
(y+xcos2(xy))dx−xdy=0
xcos2u dx−x2du =0
x2udx+xcos2(u)dx−x2du−xudx=0
xu+xcos2u dx−x2dx−xu dx=0
7
Aplicando el cambio y=xu
(y+xcos2(xy))dx−x dy=0
(xu+xcos2(xxu))dx−x(x du+u dx)=0
(xu+xcos2(u))dx−x2 du−xu dx=0
xu dx+xcos2u dx−x2du−xu dx=0
xcos2u dx−x2 du=0
8
Multiple Choice
Integrando xcos2u dx−x2du=0
∫x1dx=∫sec2u du
∫x1du=∫cos2u dx
∫x1dx=∫cos2u du
∫x dx = ∫sec2u du
9
¿Qué debemos integrar?
xcos2u dx−x2 du=0
xcos2u dx=x2du
x2xdx=cos2u1du
x1dx=sec2u du
∫x1dx=∫sec2u du
10
Multiple Choice
¿Cuáles fueron las integrales de ∫x1dx=∫sec2u du
ln(xc)=tan(xy)
ln(x+c)=tan(xy)
ln(xc)=tan(yx)
ln(xc)=sec(xy)
Otro Ejemplo
y′=xy+xcos2(xy)

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