Da função tangente

 $x=k\pi,\ k\in Z$  

 $x=\frac{\pi}{2}+k\pi,\ k\in Z$  

 $x=k\pi,\ k\in R$  

 $x=\frac{\pi}{2}+k\pi,\ k\in R$  

$x\in Z$

$x\in R$

$x\in R:\ x\ne\frac{\pi}{2}+k\pi,\ k\in Z$

$x\in\left[-1,1\right]$

$\left[-1,1\right]$

$]-\frac{\pi}{2},\ \frac{\pi}{2}[$

$\infty$

$R$

Sim

Não

$\frac{\pi}{2}$

$2\pi$

$\pi$

$\frac{\pi}{4}$

1

-1

não existem

$\pi$

 $\frac{\pi}{2}$  

 $\pi$  

 $\frac{\pi}{4}$  

 $2\pi$  

 $x=-\frac{\pi}{6}+k\pi,\ k\in Z$  

 $x=-\frac{\pi}{4}+k\pi,\ k\in Z$  

 $x=-\frac{\pi}{3}+k\pi,\ k\in Z$  

 $x=-\frac{\pi}{2}+k\pi,\ k\in Z$