Day 2 of Solutions

Presentation

•

Chemistry

•

9th - 12th Grade

•

Medium

•

NGSS

HS-PS1-5, HS-PS1-7

Standards-aligned

Daven Vandenberg

Used 2+ times

FREE Resource

8 Slides • 15 Questions

Day 2 of Solutions

I can explain how to prepare a solution of known concentration.

Multiple Choice

The ___ is the thing being dissolved

solute

solvent

Multiple Choice

Molarity is measured in

moles per kg

mols per L

moles per kJ

moles per mL

Multiple Choice

Which sweet tea would you expect to taste the sweetest?

3.1M

2.5M

Multiple Choice

What is the molarity of 4 g of NaCl (MM=58.45) in 3,800 mL of solution?

0.018 M

0.0011 M

1.052 M

0.062 M

Multiple Choice

How many liters would you need to make a 1 M solution if you have 6 mol of Sodium Hydroxide?

Multiple Choice

How many moles are needed to make 2.5 L of a 3.8 M solution?

9.5 mol

0.66 mol

1.5 mol

15 mol

Multiple Choice

When you make a dilution, which of these values remains constant?

The molarity (M)

The total moles of solute

The volume (V)

The concentration

Multiple Choice

As we dilute a solution.....

The volume increases and the molarity (M) increases

The volume increases and the molarity (M) decreases

The volume decreases and the molarity (M) increases

The volume decreases and the molarity (M) decreases

Multiple Choice

How many mL of stock solution of 2M NaCl do you need to prepare 100 mL of 0.150M NaCl?

7.5 mL

15 mL

1333 mL

200 mL

Multiple Choice

If I have 340 mL of a 0.5 M NaBr solution, what will the concentration be if I add 560 mL more water to it?

.188 M

3.78 M

.389 M

1.76 M

Multiple Choice

How do we compute for percentage by volume?

volume of solute divided by volume of solution then multiply by one hundred percent

volume of solution divided by volume of solute then multiply by one hundred percent

add volume of solute and solvent then multiply by one hundred percent

multiply volume of solute and solvent then divide by one hundred percent

Fill in the Blanks

Type answer...

Multiple Choice

How do we compute for percent by mass?

Multiple Choice

What is the percent by mass of 5.0 g of iron (II) sulfate dissolved in 75.0 g of water?

Based on the given problem what is the amount of solute?

5g iron(II) sulfate

75g water

80g solution

6.25%

Multiple Choice

What is the percent by mass of 5.0 g of iron (II) sulfate dissolved in 75.0 g of water?

Based on the given problem what is the amount of solution?

5g iron(II) sulfate

75g water

80g solution

6.25%

Day 2 of Solutions

I can explain how to prepare a solution of known concentration.

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