

Ionic Radius Trends and Multiple Ionization Energies
Presentation
•
Chemistry
•
10th - 12th Grade
•
Medium
Standards-aligned
Kristen Vanderveen
Used 403+ times
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20 Slides • 15 Questions
1
Multiple Ionization Energies
Bromfield Honors Chemistry
2
negatively charged ions
form when atoms GAIN electrons
Anions
positively charged ions
form when atoms LOSE electrons
Cations
Some text here about the topic of discussion
3
negatively charged ions
form when atoms GAIN electrons
Anions
positively charged ions
form when atoms LOSE electrons
Cations
Some text here about the topic of discussion
4
Ionic radius trends
5
Cations typically have a SMALLER radius than the parent atom
Cations vs parent ion
6
Cations typically have a SMALLER radius than the parent atom
Fewer electrons
Fewer electron:electron repulsions
Fewer occupied energy levels
7
Anions typically have a larger radius than the parent ion
Anions vs parent ion
r
Some text here about the topic of discussion.
8
More electron-electron repulsions
Anions typically have a larger radius than the parent atom
r
9
What is the trend down a group?
What is the trend across a period?
Ionic radius trends
10
Ionic radius increases down a group
Ionic radius trends
11
Ionic radius decreases from L --> R for cations
Jumps up for anions, then decreases
Ionic radius trends
12
Multiple Choice
Which of the following would have the larger radius?
Ca
Ca2+
13
Multiple Choice
Which of the following would have the larger radius?
P
P3-
14
Multiple Choice
Which of the following would have the larger radius?
Ca2+
Cl-
15
Multiple Choice
Which of the following would have the larger radius?
K+
Sc3+
16
Multiple Choice
Which of the following would have the larger radius?
Cl-
I-
17
Multiple Choice
Which of the following would have the larger radius?
P3-
S2-
18
19
The energy required to remove the outermost electron from an isolated gas phase atom
20
Multiple Choice
The equation for the first ionization energy of a sodium atom is:
Na (g) + IE ⟶ Na+ (g) + e-
Na+ (g) + IE ⟶ Na2+ (g) + e-
Na+ (g) + e- ⟶ Na (g) + IE
21
The energy required to remove a second electron
22
Multiple Choice
The equation for the second ionization energy of a sodium atom is:
Na (g) + IE ⟶ Na+ (g) + e-
Na+ (g) + IE ⟶ Na2+ (g) + e-
Na+ (g) + e- ⟶ Na (g) + IE
23
You can have as many ionization energies as there are electrons in the neutral atom
This graph shows the first 7 ionization energies for sodium
As you remove more and more electrons, it takes more and more ionization energy
24
Open Ended
Why do you think successive ionization energies increase as additional electrons are removed? Hint: Consider electron configurations in your answer.
25
Consider the values for the first and second ionization energies of sodium
26
Multiple Choice
When a neutral atom of sodium loses its first electron, the electron is removed from the ____ sublevel.
1s
2s
2p
3s
27
Multiple Choice
When a Na+ ion loses an electron, the electron is removed from the ____ sublevel.
1s
2s
2p
3s
28
Open Ended
Compare the magnitude of the first and second ionization energies of sodium.
29
Removing the first electron from Na is relatively easy
To remove a second electron from Na, we have to remove an electron from a noble gas-like electron configuration
30
We see a BIG jump in IE values once all the valence electrons have been removed
31
Multiple Choice
Why do we see a big jump in Ionization energy?
Because once an element loses all of their electrons there is no more to take
Because once an atom loses all their valence electrons, it is harder to take them away
Because once the atom becomes an ion it is harder to take electrons away
Because once the atom loses 8 electrons it is harder to take them away
32
IE2 > IE1, as expected
We see a big jump between IE2 and IE3
33
Removing both electrons from the 3s sublevel is relatively easy
Once we try to remove an electron from a fully filled energy level, it takes a LOT more energy!
This confirms 2 valence electrons for Mg
34
Multiple Choice
Successive ionization energies for an element in Period 4 were found to be:
IE1=600 kJ/mol
IE2=1800 kJ/mol
IE3=2700 kJ/mol
IE4=11,600 kJ/mol
IE5=15,000 kJ/mol
How many valence electrons does this element have?
1
2
3
4
5
35
Multiple Choice
Successive ionization energies for an element in Period 4 were found to be:
IE1=600 kJ/mol
IE2=1800 kJ/mol
IE3=2700 kJ/mol
IE4=11,600 kJ/mol
IE5=15,000 kJ/mol.
Identify the element:
germanium
selenium
gallium
silicon
phosphorous
Multiple Ionization Energies
Bromfield Honors Chemistry
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