(03/01) ALG 2 Unit 5B: Solving Log Equations

Since the log function is isloated, we can skip step 1 (THERE IS NO K!)

Step 2: Rewrite as an exponential function

 $3^2=x+12$  

Step 3: Solve for x. 

 $3^2-12=x$  

 $x=-3$  

Step 1: Isolate the log function by adding 7 to both sides!

 $\log_3x-7+7=-2+7$  

 $\log_3x=5$  

Step 2: Rewrite as an exponential function. 

 $3^5=x$  

Step 3: Solve for x

 $x=243$  

Step 1: Isolated the natural log (ln) by subtracting 27 from both sides. 

 $\ln\left(x+15\right)+27-27=31-27$  

 $\ln\left(x+15\right)=4$  

Step 2: Rewrite as a natural exponential function!  $\ln\rightarrow e$  

 $e^4=x+15$  

Solve for x by subtracting 15 on both sides  $e^4-15=x+15-15$  

 $x\approx39.60$  

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