Molarity

I must first look at what I know....

I want 250 mL of 0.5 M HCl. (V1=250 mL and M1=0.5 M)

I have 12 M HCl (V2=12 M)

I need to solve for the V2

When I solve this equation, I get 10.4 mL for V2

This means that I need 10.4 mL of 12 M HCl.

I will take 10.4 mL of 12M HCl and dilute it to 250 mL.

This will make 250 mL of a 0.5M HCl solution.

In the previous question, did you get that you needed to take 27.8 mL of 18M sulfuric acid and dilute it to a volume of 500 mL? If you did, great job!