Graphing logarithmic functions with transformations

 $y\ =\ \log_2\left(-x\right)+3$  has the following parent points:  $\left(\frac{1}{2},-1\right),\ \left(1,0\right),\ \left(2,1\right)$  What would happen after the first transformation?

 $y\ =\ \log_2\left(-x\right)+3$  has the following parent points:  $\left(\frac{1}{2},-1\right),\ \left(1,0\right),\ \left(2,1\right)$  What would happen after the second transformation?

 $y=\log_2\left(-x\right)+3$  has parent points:  $\left(\frac{1}{2},-1\right),\ \left(1,0\right),\ \left(2,\ 1\right)$  The transformations gave you: (-1x, y +3).  What would be the transformed points?

 $y=-2\log_3\left(x+1\right)$  has parent points:   $\left(\frac{1}{3},\ -1\right),\ \left(1,\ 0\right),\ \left(3,1\right)$  What is the 1st transformation?

 $y=-2\log_3\left(x+1\right)$  has parent points:   $\left(\frac{1}{3},\ -1\right),\ \left(1,\ 0\right),\ \left(3,1\right)$  What is the 2nd transformation?

 $y=-2\log_3\left(x+1\right)$  has parent points:   $\left(\frac{1}{3},\ -1\right),\ \left(1,\ 0\right),\ \left(3,1\right)$  Transformations gave the rule (x - 1, -2y).  What are the points of the new function?