Staying in Balance! (1-Step)

Constant

Coefficient

Solution

Variable

Variable

Coefficient

Equation

Solution

Coefficient

Variable

Solution

Equation

Coefficient

Variaable

Solution

Equation

20

2

x

a

3

+

4

y

$x\cdot x\cdot x=1\cdot1\cdot1\cdot1\cdot1\cdot1$

$x\cdot x\cdot x=6$

$3x\ =\ 6$

$x+3=6$

$13\ \frac{4}{5}=w\ +\ 3\ \frac{4}{5}$

$13\ \frac{4}{5}\ =\ 3\ \frac{4}{5}\cdot w$

$12\ =\ 2\ +\ y$

$12=2y$

$3\ \cdot\ x\ =\ 8$

$3\ +\ x\ =\ 8$

x and 3 together must equal 8, so x is 5 because 5 + 3 = 8

x and 3 together must equal 8, so x is 4 because 4 + 3 = 8

Remove 3 from both sides to keep the hanger balanced. X is 5 since 8 - 3 is 5.

Remove x from both sides to keep the hanger balanced. 3 = 8

y = 12. 12 is twice the weight of y, so y weighs half of 6.

y = 6. 12 is twice the weight of y, so y weighs half of 12.

Dividing each side of the equation by 4 leaves 11/4 = z.

Dividing each side of the equation by 2 leaves 22/4 = z .