(01/12) 6th Period CRM: Solving by Substuition & Graphing

Presentation

•

Mathematics

•

11th - 12th Grade

•

Medium

•

CCSS

HSA.REI.C.9

Standards-aligned

Beatrice Thames

Used 1+ times

FREE Resource

1 Slide • 10 Questions

(01/12) 6th Period CRM: Solving Systems by Substuition (EC)

Complete for extra credit on your 1st quiz Friday (01/15)

Multiple Choice

Solve:

y = -1x - 5

4x - 8y = 4

(-3, -2)

(5, -7)

(3, 9)

(-5, 4)

Multiple Choice

Solve each system of equations.

y = 3x - 11

2x + 3y = 0

(-2,3)

(-3,2)

(3,-2)

(2,-3)

Multiple Choice

Solve the system by substitution.

5x + 4y= −14

y = −7x − 15

(-2, -1)

(1, -2)

(-2, 1)

(-1, -2)

Multiple Choice

3x + 2y = 8

-x + y = -11

(-5,6)

(6,-11)

(-6,-5)

(6,-5)

Multiple Choice

The solution to a system of equations is any ordered pair that makes both equations true.

TRUE

FALSE

Multiple Choice

What is the solution to the system of equations?

y = 3x - 8

y = 4 - x

(3,1)

(1,3)

(-3,1)

(3,-1)

Multiple Choice

How many solutions will this system have?

No solution

One Solution

I Don't Know

Infinitely Many Solutions

Multiple Choice

What is the solution?

One Solution

No solution

Infinitely Many Solutions

Multiple Choice

What is the solution to the system?

(0, 3)

(1, -1)

(-3, 1)

(1, 3)

Multiple Choice

These two lines intersect at _____.

(4, -2)

(4, 2)

(-2, 4)

No solution

(01/12) 6th Period CRM: Solving Systems by Substuition (EC)

Complete for extra credit on your 1st quiz Friday (01/15)

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