Quadratic Functions Day 2 Lesson Slides: 5 Slides

5 Slides • 5 Questions

1

Quadratic Functions Day 2

Tuesday Dec 15, 2020

2

Multiple Choice

Warm - up: How do you find the zeros of a quadratic function?

1

Make one factor equal 0, so the whole thing is 0

2

Set each factor equal to zero, and solve for x

3

You don't

4

What?

3

Recap from yesterday...

The zeros of a quadratic function are where the function crosses the x-axis (this was called the x-intercept in linear functions)

You find the zeros by setting each factor equal to zero and solving for x

Zeros are written as ordered pairs (x, 0) where x is a number

4

Multiple Choice

What are the zeros of this function?

$y\ =\ \left(8x+2\right)\left(x-5\right)$

Remember to write fractions in simplest form

1

(-2, 8), (-5, 0)

2

$\left(-\frac{2}{8},\ 0\right),\ \left(5,\ 0\right)$

3

$\left(-\frac{1}{4},\ 0\right),\ \left(5,\ 0\right)$

4

There aren't any

5

Now, let's find the y-intercept

To find the y-intercept, plug in 0 for all the x values and solve

$y=\left(x-8\right)\left(8x-5\right)$

y=\left(0-8\right)\left(8\left(0\right)-5\right)

y=\left(-8\right)\left(-5\right)

y=40

y-intercept: (0,40)

6

Open Ended

Find the y-intercept:

$y=\left(x-3\right)\left(5x+6\right)$

Type response here

7

Sometimes you need to factor first

y=x^2-2x-24

8

Multiple Choice

Factor:

y=x^2-2x-24

1

(x + 6)(x - 4)

2

(x - 6)(x - 4)

3

(x - 6)(x + 4)

4

Not factorable

9

Multiple Choice

What's the y-intercept of

$y=\left(x-6\right)\left(x+4\right)$

1

(4, 0)

2

(-4, 0)

3

(0, 4)

4

(0, -4)

10

Go practice

There's a practice sheet for you in Google Classroom

Quadratic Functions Day 2

Tuesday Dec 15, 2020

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