3.5 Notes Part 1 - Solve Nonlinear Systems

3 Slides • 1 Question

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2

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Solve the system using substitution:

x² = 2y + 10

3x - y = 9

Solve equation 2 for y: y = 3x - 9
Substitute equation 2 into equation 1: x² = 2(3x - 9) + 10
Simplify: x² = 6x - 18 + 10 Simplify: x² = 6x - 8
Write in standard form: x² - 6x + 8 = 0
Factor: (x - 4)(x - 2) = 0
Use zero product property: x - 4 = 0 or x - 2 = 0 Solve, x = 4 or x = 2
Plug back into equation 2: y = 3(4) - 9 = 3 (4, 3) / y = 3(2) - 9 = -3 (2, -3)

4

Multiple Choice

Find the solution.

1

(2,3) and (3,4)

2

(-3,-15) and (4,-8)

3

(-3,10) and (8,4)

4

(-8,3) and (-4,10)

3.5 Notes Part 1 - Solve Nonlinear Systems

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3.5 Notes Part 1 - Solve Nonlinear Systems_Alg2

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