Menentukan Fungsi Kuadrat

f(x) = 2x² – 12x + 12

f(x) = 2x² – 12x + 12

f(x) = -2x² + 12x – 12

f(x) = -2x² + 12x + 12

f(x) = -2x² - 12x - 12

y = 2x² – 4x + 4

y = 2x² + 4x + 4

y = -2x² – 4x + 4

y = -2x² + 4x + 4

y = -2x² - 4x - 4

f(x)=x² + 4x + 4

f(x)=x² - 4x + 4

f(x)=x² - 4x - 4

f(x)=x² + 2x + 4

f(x)= -x² - 4x - 4

$f\left(x\right)=x^2+4x$

$f\left(x\right)=x^2-4x$

$f\left(x\right)=-x^2+4x$

$f\left(x\right)=-x^2-4x+4$

$f\left(x\right)=-x^2-4x$