$\left(8x^4-3x^2+2\right)+\left(10x^2-9x-5\right)$  

 $\left(8x^4-3x^2+2\right)-\left(10x^2-9x-5\right)$  

 $\left(8x^4-3x^2+2\right)\left(10x^2-8x-5\right)$  

 $10\left(8x^4-3x^2+2\right)-9\left(8x^4-3x^2+2\right)-5$  

 $8x^4-3x^2+2+10x^2-9x-5$  

 $8x^4-3x^2+2-10x^2+9x+5$  

 $\left(8x^4-3x^2+2\right)\left(10x^2-8x-5\right)$  

 $10\left(8x^4-3x^2+2\right)-9\left(8x^4-3x^2+2\right)-5$  

 $10\left(8x^4-3x^2+2\right)^2-9\left(8x^4-3x^2+2\right)-5$  

 $\left(8x^4-3x^2+2\right)\left(10x^2-9x-5\right)$  

 $8\left(10x^2-9x-5\right)^4-3\left(10x^2-9x+5\right)^2+2$  

 $8\left(10x^2-9x-5\right)^4-3x^2+2$  

 $10\left(8x^4-3x^2+2\right)-9x-5$  

 $10\left(8x^4-3x^2+2\right)^2-9\left(8x^4-3x^2+2\right)-5$  

 $\left(8x^4-3x^2+2\right)\left(10x^2-9x-5\right)$  

 $8\left(10x^2-9x-5\right)^4-3\left(10x^2-9x+5\right)^2+2$  

 $8\left(10x^2-9x-5\right)^4-3x^2+2$  

 $10\left(8x^4-3x^2+2\right)-9x-5$  

(5x-9)(5x²-3x+2)

2(5x-9)+2(5x²-3x+2)

(5x-9)(5x²-3x+2)

(5x²-3x+2) / (5x-9)

(25x³-60x²+37x-18) + (4x²-12x+9)

(25x³-60x²+37x-18) - (4x²-12x+9)

(4x²-12x+9) - (25x³-60x²+37x-18)

(2x-3)(25x³-60x²+37x-18)

(4x²-12x+9) (25x³-60x²+37x-18)

8d²-2d+7+11d+15

88d³-22d²+77d+120d²-30d+105

8d²-2d+7-11d-15

5x²+2x-4+6x²-2x-9

5x²+2x-4-6x² +2x+9

6x²-2x-9-5x²-2x+4

30x⁴-10x³-45x²+12x³-4x²-18x-24x²+8x+36

the x's and y's are switched

the x's and y's are divided by 2

the x's and y's are made negative

the x's and y's are the same

no,

yes

f ^-1(x) = 3x + 5

f ^-1(x) = 3x - 5

f ^-1(x) = 3x - 15

f ^-1(x) = 3x + 15

f^-1(x) = 4x - 3

f^-1(x) = -1/4x - 3

f^-1(x) = 1/4x + 3

f^-1(x) = -4x - 3

Good

Ok, I need to study a little

Kind of iffy, I will be studying

I have no idea what's going on in this class

review class powerpoints

review quizizz answer keys

do aleks practice problems

look up videos on youtube

practice on khan academy