

Zearn Mission 3 Lesson 3
Presentation
•
Mathematics
•
4th Grade
•
Hard
+1
Standards-aligned
Karyssa ES]
Used 3+ times
FREE Resource
5 Slides • 5 Questions
1
Mission 3 Lesson 3
I can solve real-world problems involving area and perimeter or rectangles.

2
Problem 1
The rectangular projection screen in the school auditorium is 5 times as long and 5 times as wide as the rectangular screen in the library. The screen in the library is 4 feet long with a perimeter of 14 feet. What is the perimeter of the screen in the auditorium?
3
Multiple Choice
Which screen is bigger?
The rectangular projection screen in the school auditorium is 5 times as long and 5 times as wide as the rectangular screen in the library. The screen in the library is 4 feet long with a perimeter of 14 feet. What is the perimeter of the screen in the auditorium?
auditorium
library
4
Let's solve
Go back to the meets to write in your notes. Do not click the X because we will be coming back to this.
5
Problem 5
The width of David’s rectangular tent is 5 feet. The length is twice the width. David’s rectangular air mattress measures 3 feet by 6 feet. If David puts the air mattress in the tent, how many square feet of floor space will be available for the rest of his things?
6
Multiple Choice
What are we going to need to find out?
The width of David’s rectangular tent is 5 feet. The length is twice the width. David’s rectangular air mattress measures 3 feet by 6 feet. If David puts the air mattress in the tent, how many square feet of floor space will be available for the rest of his things?
The area of both the tent and air mattress?
The perimeter of both the tent and the air mattress.
I do not know.
7
Fill in the Blanks
Type answer...
8
Fill in the Blanks
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9
Multiple Choice
What is our last step?
The width of David’s rectangular tent is 5 feet. The length is twice the width. David’s rectangular air mattress measures 3 feet by 6 feet. If David puts the air mattress in the tent, how many square feet of floor space will be available for the rest of his things?
Add 50 square feet and 18 square feet.
Subtract 50 square feet and 18 square feet.
Multiply 50 square feet and 18 square feet.
Divide 50 square feet and 18 square feet.
Nothing, we are done. The answer is 50 square feet and 18 square feet.
10
Problem 3
Jackson’s rectangular bedroom has an area of 90 square feet. The area of his bedroom is 9 times that of his rectangular closet. If the closet is 2 feet wide, what is its length?
Mission 3 Lesson 3
I can solve real-world problems involving area and perimeter or rectangles.

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