Factoring to find the x-intercepts

 $6x^3+8x^2+3x+4$  

 $4x^2+3x-2$  

 $6x^3+3x+8x+4$  

48

 $\frac{48}{47}$  

47

no solution 

 $\frac{1}{15}$  

 $-\frac{1}{15}$  

 $\frac{1}{15\ }and\ -\frac{1}{15}$  

no solution 

7

2

2 and 7

44

24

24, 1

7

-24, -1

 $3\ and\ -\frac{2}{3}$  

 $-\frac{2}{3}$  

 $Imaginary\ number\$  

 $7\ and\ 8$  

 $11\ and\ \frac{1}{4}$  

 $11\ and\ -\frac{1}{4}$  

 $-11\ and\ \frac{1}{4}$  

 $-\frac{1}{4}\ and\ -11$