Le componenti di un vettore $$\overrightarrow{\ v}=\overrightarrow{AB}$$ con $$A\left(x_1,\ y_1,\ z_1\right)$$ e $$B\left(x_2,\ y_2,\ z_2\right)$$ si ottengono come...

... differenza delle coordinate di B e A: $$\overrightarrow{\ v}\left(x_2-x_1,\ y_2-y_1,\ z_2-z_1\right)$$ .

Il vettore ottenuto sommando $$\overrightarrow{\ v}\left(2,\ 3,\ -5\right)$$ e $$\overrightarrow{\ w}=\left(-4,\ 1,\ 7\right)$$ è...

$$\overrightarrow{\ u}=\left(-2,\ 4,\ 2\right)$$

Due modi per definire il prodotto scalare tra due vettori $$\overrightarrow{\ a}$$ e $$\overrightarrow{\ b}$$ .

$$\overrightarrow{\ a}\cdot\overrightarrow{\ b}=\left|\vec{a}\right|\ \cdot\ \left|\vec{\ b}\right|\cdot\ \cos\left(\theta\right)$$ , dove $$\theta$$ è l'angolo formato dai due vettori, oppure, usando le componenti dei due vettori: $$\vec{\ a\ }\cdot\ \vec{\ b}\ =a_xb_x+a_yb_y+a_zb_z$$ .

Verifica prerequisiti per piano nello spazio Flashcards

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FLASHCARD QUESTION

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FLASHCARD QUESTION

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FLASHCARD QUESTION

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Due vettori non nulli sono perpendicolari se e solo se il loro prodotto scalare è nullo. Vero perché? Falso perché?

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