
Product & Chain Rule
Flashcard
•
Mathematics
•
12th Grade
•
Practice Problem
•
Hard
Wayground Content
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14 questions
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1.
FLASHCARD QUESTION
Front
Define the Product Rule in calculus.
Back
The Product Rule states that if you have two functions u(x) and v(x), the derivative of their product is given by: \( (uv)' = u'v + uv' \).
2.
FLASHCARD QUESTION
Front
Define the Chain Rule in calculus.
Back
The Chain Rule is used to differentiate composite functions. If \( y = f(g(x)) \), then the derivative is given by: \( \frac{dy}{dx} = f'(g(x)) \cdot g'(x) \).
3.
FLASHCARD QUESTION
Front
Differentiate the function:
Back
Using the Product Rule, the derivative is: \( y' = (2)(5x - 4) + (2x + 1)(5) = 20x - 8 + 10x + 5 = 20x - 3 \).
4.
FLASHCARD QUESTION
Front
Differentiate the function:
Back
Using the Product Rule, the derivative is: \( y' = 2x^2(3) + (2)(2x)(3x - 4) = 6x^2 - 16x \).
5.
FLASHCARD QUESTION
Front
Differentiate the function:
Back
Using the Product Rule, the derivative is: \( y' = (2x)(x + 7) + (x^2 - 1)(1) = 2x^2 + 14x + x^2 - 1 = 3x^2 + 14x - 1 \).
6.
FLASHCARD QUESTION
Front
Differentiate the function:
Back
Using the Chain Rule, the derivative is: \( y' = cos(2x^2) \cdot (4x) = 4x cos(2x^2) \).
7.
FLASHCARD QUESTION
Front
Set up the derivative for:
Back
Using the Product Rule, the derivative is: \( y' = (3x^4 - 7)(10x) + (12x^3)(5x^2 + 1) \).
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